Michigan State University - Diagnostic Exam

1.17

  •   The graph below is the solution set for which values of x?

    PIC



    a) |x - 1|≥ 5 b) |x - 1|≥ 3 c) |x + 1|≥ 4
       
    d) |x + 1|≤ 4 e) -5 x 3

Solution:
               x ≤  - 5 or x ≥ 3  ⇒

x + 1 ≤ - 5 + 1 or x + 1 ≥ 3 + 1  ⇒

                     |x + 1| ≥ 4

Diagnostic:

If you miss this question please review absolute value inequalities. Also, review compound inequalities.

See 1.5: Linear Inequalities .


July 15, 2008