Michigan State University - Diagnostic Exam

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4.10

  •   What is the equation of the line of symmetry of the parabola y = 3x2 - 12x - 7.

    a) y = -7 b) y = 2 c) x = 2 d) y = 1 -- 4 e) x = 4

Solution:

y=3x2- 12x - 7 = 3(x2 - 4x + 4) - 7 - 12 = 3(x - 2)2 - 19 . It follows that the axis of symmetry is x=2 .

Diagnostic:

See 4.1: Graphing (Quadratic Functions) .

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July 15, 2008