Fractional Equations

Michigan State University - Diagnostic Exam

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1.2

If $1- 3- 1- r + 5 = 2$ , then r =(?).

a) $10$ b) $3 -- 2$ c) $2 -- 3$ d) $- 10$ e) $3 - -- 2$

Solution:

$( ) 1- 3- 1- ⇒ 10r r + 5 = 2 ⇒ 10 + 6r = 5r ⇒ r = - 10$

Diagnostic:

If you miss this question please review equations with fractions.

Also see 1.1: Linear Equations .

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July 15, 2008