Literal Equations (Linear)

Michigan State University - Diagnostic Exam

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1.3

Solve the equation ab + mk = 3a for a.

a) $-mk-- 3 - b, b ⁄= 3$ b) $mk--- b - 3 , b ⁄= 3$ c) $ab +-mk-- 3$

d) $3a---mk-- b , b ⁄= 0$ e) $a(b - 2) + mk$

Solution:

$mk ⇒ 3a - ab = mk ⇒ a(3 - b) = mk ⇒ a = -----, b ⁄= 3 3 - b$

Diagnostic:

If you miss this question please review literal equations.

Also see 1.1: Linear Equations .

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July 15, 2008