Michigan State University - Diagnostic Exam

 [next]  [prev]  [bottom]  [up] 

4.7

  •   Which of the following is the equation of a parabola with y-intercept at the origin and vertex at (2, 5)?

    a)  5 y = --x2 4 b) x = (y - 5)2 + 2 c)  5 y = -(x + 2)2 - 5 4
       
    d)  5 x = -(y + 5)2 - 2 4 e)  - 5 y = --- (x - 2 )2 + 5 4

Solution:

The equation has the form 2 y = a (x - 2) + 5 and 2 - 5- x = y = 0 ⇒ 0 = a (0 - 2) + 5 ⇒ a = 4 .

Diagnostic:

See 2.7: Application (Reading Graphs) and 4.1: Graphing (Quadratic Functions) .

 [next]  [prev]  [top]  [up] 

July 15, 2008