Michigan State University - Diagnostic Exam

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4.8

  •   The common denominator of least degree of -----1------ x2 - 4x + 3 and 1 2--------- x- 2x + 1 is?

    a) (x - 1)2 b) (x - 1)2(x - 3) c) (x - 1)3(x - 3)
       
    d) (x - 1)2(x + 3) e) (x - 4)(x + 3)

Solution:

Since 2 x - 4x + 3 = (x - 1 )(x - 3) and 2 2 x - 2x + 1 = (x - 1) , the LCD is 2 (x - 3)(x - 1) .

Diagnostic:

If you miss this question please review finding the least common denominator.

Also, see 1.9: Factoring (Polynomials) .

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July 15, 2008